Elimination Method of Finding Solution of a Pair of Linear Equations
The cost of 3...
Question
The cost of 3 horses and 5 cows is Rs.20,500 and the cost of 2 horses and 3 cows is Rs.13,400. Find the cost of one horse and one cow. Also, find the total cost of 5 horses and 4 cows.
A
Cost of one horse =Rs.5,500 Cost of one cow =Rs.800 Cost of 5 horses and 4 cows =Rs.30,700
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B
Cost of one horse =Rs.6,000 Cost of one cow =Rs.900 Cost of 5 horses and 4 cows =Rs.33,600
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C
Cost of one horse =Rs.4,000 Cost of one cow =Rs.500 Cost of 5 horses and 4 cows =Rs.22,000
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D
Cost of one horse =Rs.3,000 Cost of one cow =Rs.1,000 Cost of 5 horses and 4 cows =Rs.19,000
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Solution
The correct option is A Cost of one horse =Rs.5,500 Cost of one cow =Rs.800 Cost of 5 horses and 4 cows =Rs.30,700 Let x rupees and y rupees be the cost of one horse and one cow respectively. Therefore, according to the question, 3x+5y=20500 ...(i) 2x+3y=13400 ...(ii) On multiplying (i) by 2 and (ii) by 3 and subtracting, we get 6x+10y=41000 6−x+−9y=4−0200––––––––––––––––– y=800 On putting y=800 in (i), we get 3x+4000=20500⇒x=5500 ∴cost of one horse=Rs. 5500 and cost of one cow=Rs.800 Now, the cost of 5 horses and 4 cows=5×5500+4×800=Rs.30700