The cost of 3 kg of apples and 2 kg of grapes on a day was found to be Rs- 160- After a month the cost of 4 kg of apples and 2 kg of apples and 2 kg of grapes is Rs- 300- Represent the situation as a pair of liner equation in two variables-

Let apples be Xand grapes be YOn first day, 3 kg of apples and 2 kg of grapes was 160 3X + 2Y=160. After one month 4 kg and 2 kg o ...

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Standard IX

Mathematics

Ratio and Proportion

The cost of ...

Question

The cost of $3 k g$ of apples and $2 k g$ of grapes on a day was found to be $R s . 160$ . After a month the cost of $4 k g$ of apples and $2 k g$ of grapes is $R s . 300$ . Represent the situation as a pair of liner equation in two variables.

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Solution

Let
cost of $1 k g$ apples be $x$ and
the cost of $1 k g$ grapes be $y$

On first day, $3 k g$ of apples and $2 k g$ of grapes was $R s 160$
So, $3 x + 2 y = 160$ ......................... (1)

After one month $4 k g$ of apples and $2 k g$ of grapes was $R s 300.$
So, $4 x + 2 y = 300$ ...........................(2)
From eq (1) and (2), the given situation can be represented by following pair of equations.
$3 x + 2 y = 160$
$4 x + 2 y = 300$

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