The cost of a bike depreciates at the rate of $20 %$ every year. If its present worth is ₹30000, find the purchase value of the bike after the end of 3 years.

₹ 15470

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₹ 16350

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₹ 19200

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₹ 15360

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Solution

The correct option is D ₹ 15360
Given,
P = ₹ 30000
r = 20 %
n = 3 years

Let A be the value of the bike after 3 years.

$A = P (1 - \frac{20}{100})^{3}$
$A = 30000 (1 - \frac{1}{5})^{3}$
$A = 30000 (\frac{4 \times 4 \times 4}{5 \times 5 \times 5})$
$A = ₹ 15360$

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The cost of a bike depreciates at the rate of 20% every year. If its present worth is ₹30000, find the purchase value of the bike after the end of 3 years.

The correct option is D ₹ 15360Given, P = ₹ 30000 r = 20 % n = 3 years Let A be the value of the bike after 3 years. A=P(1−20100)3 A=30000(1−15)3 A=30000(4 × 4 × 45 × 5× 5) A=₹ 15360

The cost of a bike depreciates at the rate of $20 %$ every year. If its present worth is ₹30000, find the purchase value of the bike after the end of 3 years.

The correct option is D ₹ 15360
Given,
P = ₹ 30000
r = 20 %
n = 3 years

Let A be the value of the bike after 3 years.

$A = P (1 - \frac{20}{100})^{3}$
$A = 30000 (1 - \frac{1}{5})^{3}$
$A = 30000 (\frac{4 \times 4 \times 4}{5 \times 5 \times 5})$
$A = ₹ 15360$