The cost of a bottle and a bowl together is 92 rupees. If the bottle costs 20 rupees more than the bowl, then what is the price of one bottle is
56 rupees
Let the cost of one bottle be x rupees and the cost of one bowl be y rupees.
Given, cost of a bottle and a bowl together is 92 rupees.
So, x+y=92 ---------- (i)
Also, given that, the bottle costs 20 rupees more than the bowl.
So, x=y+20 ---------- (ii)
Substituting (ii) in (i), we get,
(y+20)+y=92
⟹(20+y)+y=92 [x+y=y+x for all numbers x, y]
⟹20+(y+y)=92
⟹20+2y=92 [Since y+y=2y for any number y]
⟹2y=72
⟹y=36
x+y=92 and y=36 implies x=56
Therefore the price of one bottle is 56 rupees.