We have P=Rs.24,000, R=10% and T=6 months=1/2 year. Here is no down payment. Hence the principal is P = Rs. 24,000. But we know that E=nI−P. Substitute this in the relation
R=2400×En((n+1)×I−2E).
We get
R=2400(nI−P)n[(n+1)I−2(nI−P)]=2400(nI−P)n[2−(n−1)I]
Hence
nIR(2P−(n−1)I)=2400nI−2400P.
This gives
nIR×(2400+(n−1)R)=P(2nR+2400).
We get a formula for I:
I=P(2nR+2400)n(2400+(n−1)R).
Here P=24000, n=6, R=10. Substituting these and simplifying the expression,
we obtain
I=24000[(2×6×10)+2400]6[2400+(5×10)]=20160049≈4114.30.
The monthly EMI is approximately Rs. 4,114.30. The total amount paid by her is
4114.30×6≈Rs.24,686.