The cost of a machine depreciated by Rs. 4,000 during the first year and by Rs. 3,600 during the second year. Calculate its cost at the end of the third year
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Solution
Difference between depreciation of 1st year and 2nd year=4000−3600=Rs.400
⇒Depreciation of one year on Rs.4000=Rs.400
⇒Rate of depreciation =400×1004000=10%
Let the original cost of the machine be Rs100
∴Value after one year=Rs.100−10%of100=100−10100×100=Rs.90
Depreciation during second year=10% of 90=10100×90=Rs.9
When depreciation during second year is Rs. 9 then original cost=Rs.100
When Depreciation during the second year is Rs.3600 then original cost=1009×3600=Rs.40000
Cost of the machine after one year=40000−4000=Rs.36000
Cost of the machine after second year=36000−3600=Rs.32400
∴Depreciation in third year=10%of 32400=10100×32400=Rs.3240
Cost of the machine after third year=32400−3240=Rs.29160