The cost of a machine is ₹2,50,000. It depreciates at the rate of 4% per annum. Find the cost of the machine after three years.

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Solution

Cost of a machine = ₹2,50,000
Rate of depreciation = 4%
Time period = 3 years
$A = P {(1 - \frac{r}{100})}^{n} \Rightarrow A = 250000 {(1 - \frac{4}{100})}^{3} \Rightarrow A = 250000 {(\frac{96}{100})}^{3} \Rightarrow A = 2, 21, 184$
Amount after three years = Rs 2,21,184

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The cost of a machine is ₹2,50,000. It depreciates at the rate of 4% per annum. Find the cost of the machine after three years.

Cost of a machine = ₹2,50,000 Rate of depreciation = 4% Time period = 3 years A=P1-r100n⇒A=2500001-41003⇒A=250000961003⇒A=2,21,184 Amount after three years = Rs 2,21,184

Cost of a machine = ₹2,50,000
Rate of depreciation = 4%
Time period = 3 years
$A = P {(1 - \frac{r}{100})}^{n} \Rightarrow A = 250000 {(1 - \frac{4}{100})}^{3} \Rightarrow A = 250000 {(\frac{96}{100})}^{3} \Rightarrow A = 2, 21, 184$
Amount after three years = Rs 2,21,184