The correct option is B 2p
Given, ₹546 is the cost of p articles.
We know that, the higher the sum spent, the number of articles one can buy is more.
So, Sum spent(x) ∝ Number of articles(y)
∴ x1y1 = x2y2
Given,
x1 = 546
y1 = p
x2 = 1638
and, y2 = Number of articles
⇒ 546p = 1638y2
⇒ y2 = 1638 × p546 = 3p
So, the number of articles bought for ₹1,638 is 3 times the number of article that was bought for ₹546.
i.e., 3p −p = 2p more articles