The cost of a refrigerator depreciates at the rate of $10 %$ every year. If its present worth is ₹ 14000, find the purchase value of the refrigerator brought 2 years before.

₹ 14982

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₹ 16381

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₹ 15476

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₹ 17284

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Solution

The correct option is D ₹ 17284
Given,
A = ₹ 14000
r = 10 %
n = 2 years

Let P be the value of the refrigerator two years ago.

$A = P (1 - \frac{10}{100})^{2}$
$14000 = P (1 - \frac{1}{10})^{2}$
$14000 = P (\frac{9 \times 9}{10 \times 10})$
$P = \frac{14000 \times 10 \times 10}{9 \times 9}$
$P = ₹ 17284$

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The cost of a refrigerator depreciates at the rate of 10% every year. If its present worth is ₹ 14000, find the purchase value of the refrigerator brought 2 years before.

The correct option is D ₹ 17284Given, A = ₹ 14000 r = 10 % n = 2 years Let P be the value of the refrigerator two years ago. A=P(1−10100)2 14000=P(1−110)2 14000=P(9 × 910 × 10) P=14000 × 10 × 109 × 9 P=₹ 17284

The cost of a refrigerator depreciates at the rate of $10 %$ every year. If its present worth is ₹ 14000, find the purchase value of the refrigerator brought 2 years before.