The cost of fencing a rectangular field at $R s 18$ per metre is $R s 1980$ . If the width of the field is $23 m$ find its length.

Open in App

Solution

The perimeter of the rectangle field $= \frac{1980}{18} = 110 m$

The width of the field $= 23 m$

We know that
$2 (l e n g t h + w i d t h) = 110$

Therefore,
$2 (l e n g t h + 23) = 110$

$l e n g t h + 23 = 55$

$l e n g t h = 32 m$

Hence, this is the answer.

Suggest Corrections

Similar questions

Q. The cost of fencing a rectangular field at Rs 18 per metre is Rs 1980. If the width of the field is 23 m, find its length.

The cost of cultivating a rectangular field at $R s .35$ per square metre is $R s . 71400$ . If the width of the field is $40$ m, find its length. Also, find the cost of fencing the field at $R s .50$ per metre.

Q. The cost of fencing a rectangular field at Rs 30 per metre is Rs 2400. If the length of the field is 24 m, then its breadth is
(a) 8 m
(b) 16 m
(c) 18 m
(d) 24 m

Q. The length of a rectangular field is thrice its breadth . If the area of the field is 7500m sq. ,find the cost of fencing the field at the rate Rs 10 per metre sq.

Q. The cost of fencing a rectangular field of length 100 m and breadth 40 m is , if it costs ₹ 15 per metre.

Join BYJU'S Learning Program

The cost of fencing a rectangular field at Rs18 per metre is Rs1980. If the width of the field is 23m find its length.

The perimeter of the rectangle field =198018=110 mThe width of the field =23 mWe know that2(length+width)=110Therefore,2(length+23)=110length+23=55length=32 mHence, this is the answer.

The cost of fencing a rectangular field at $R s 18$ per metre is $R s 1980$ . If the width of the field is $23 m$ find its length.

The perimeter of the rectangle field $= \frac{1980}{18} = 110 m$

The width of the field $= 23 m$

We know that
$2 (l e n g t h + w i d t h) = 110$

Therefore,
$2 (l e n g t h + 23) = 110$

$l e n g t h + 23 = 55$

$l e n g t h = 32 m$

Hence, this is the answer.