The cost of painting the total outer surface of a closed cylindrical oil tank at $60$ paise per sq. cm is $R s . 247.60$ . The height of the tank is $6$ times the radius of the base of the tank. Find height and radius of the tank. $(U s e π = \frac{22}{7})$ .

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Solution

Let the radius = r dm
then height = 6r dm
volume of cylinder= $π r^{2} h$
= $π r^{2} \times 6 r$
the cost of painting the cylinder 60 paise per dm2 is given by 247.60
$i . e . v o l u m e \times 0.6 = 247.60$
$v o l u m e = \frac{247.60}{0.6}$
$v o l u m e = 412.66$

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The cost of painting the total outer surface of a closed cylindrical oil tank at 60 paise per sq. cm is Rs.247.60. The height of the tank is 6 times the radius of the base of the tank. Find height and radius of the tank. (Use π=227).

Let the radius = r dmthen height = 6r dmvolume of cylinder= πr2h = πr2×6rthe cost of painting the cylinder 60 paise per dm2 is given by 247.60i.e.volume×0.6=247.60volume=247.600.6volume=412.66

The cost of painting the total outer surface of a closed cylindrical oil tank at $60$ paise per sq. cm is $R s . 247.60$ . The height of the tank is $6$ times the radius of the base of the tank. Find height and radius of the tank. $(U s e π = \frac{22}{7})$ .

Let the radius = r dm
then height = 6r dm
volume of cylinder= $π r^{2} h$
= $π r^{2} \times 6 r$
the cost of painting the cylinder 60 paise per dm2 is given by 247.60
$i . e . v o l u m e \times 0.6 = 247.60$
$v o l u m e = \frac{247.60}{0.6}$
$v o l u m e = 412.66$