The cost of two red balls and five blue balls is ₹160. Then find the correct equation for this situation among the given options.
$(r : price of one red ball)$
$(b : price of one blue ball)$

2 r + 5 b = ₹ 160

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3 r + 5 b = ₹ 160

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r + 5 b = ₹ 80

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2 r - 5 b = ₹ 160

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Solution

The correct option is A $2 r + 5 b = ₹ 160$
Given:

Cost of one Red ball = $r$ .

Cost of one Blue ball = $b$ .

So, the required algebraic equation will be $2 r + 5 b = ₹ 160$

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The cost of two red balls and five blue balls is ₹160. Then find the correct equation for this situation among the given options.
$(r : price of one red ball)$
$(b : price of one blue ball)$

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The cost of two red balls and five blue balls is ₹160. Then find the correct equation for this situation among the given options. (r:price of one red ball) (b:price of one blue ball)

The correct option is A 2r+5b=₹160Given: Cost of one Red ball = r. Cost of one Blue ball = b. So, the required algebraic equation will be 2r+5b=₹160

The cost of two red balls and five blue balls is ₹160. Then find the correct equation for this situation among the given options.
$(r : price of one red ball)$
$(b : price of one blue ball)$

The correct option is A $2 r + 5 b = ₹ 160$
Given:

Cost of one Red ball = $r$ .

Cost of one Blue ball = $b$ .

So, the required algebraic equation will be $2 r + 5 b = ₹ 160$