Question

The cost of two tables and $8$ chairs is $Rs.2200$. If the table costs $Rs.150$ more than a chair, find the cost of each.

Answer 1

Let the cost of table be $=x$

cost of chair be $=y$

$2x+5y=2300⟶\left(I\right)$

table cost $Rs30$ more than chain

$x=30+y⟶\left(II\right)$

Substituting value of $x$ in $\left(1\right)$

$2(30+y)+5y=2300$

$60+2y+5y=2300$

$7y=2300-60$

$y=\frac{2240}{7}$

$y=320$

Cost of chair $=Rs320$

Cost of table $=320+30=Rs350$.