Question

The cost of two tables and three chairs is $\$805$.If the table costs $\$60$ more than the chair, find the cost of the table and the chair.

• A. $\$197,\$127$
• B. $\$127,\$157$
  
• C. $\$167,\$127$
• D. $\$197,\$137$

Answer 1

The correct option is D $\$197,\$137$

The table cost $\$40$ more than the chair.
Let us assume the cost of the chair to be $x.$
Then the cost of the table $=\$60+x$
The cost of $3$ chairs $=3\times x=3x$ and the cost of $2$ tables $2(60+x)$
Total cost of $2$ tables and $3$ chairs $=\$805$
Therefore,
$2(60+x)+3x=805$
$120+2x+3x=805$
$120+5x=805$
$5x=805-120$
$5x=685$
$x=\frac{685}{5}=137$
Hence, $x=137\text{and}x+60=137+60=197$

Therefore, the cost of each chair is $\$137$ and that of each table is $\$197$.