The cost of using a telephone in a hotel meeting room is 0.20 $p e r m i n u t e . W h i c h o f t h e f o l l o w i n g e q u a t i o n s r e p r e s e n t s t h e t o t a l c o s t$ c $, i n d o l l a r s, f o r$ h$ hours of phone use?

c = 0.20 (60 h)

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c = 0.20 h + 60

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c = \frac{60 h}{0.20}

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c = \frac{0.20 h}{60}

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Solution

The correct option is A $c = 0.20 (60 h)$
The hotel charges $$ 0.20$ per minute to use the meeting‑room phone.
This per‑minute rate can be converted to the hourly rate using the conversion $1$ hour $= 60$ minutes, as shown in the following equation.
$\frac{0.20}{m i n u t e} \times \frac{60 m i n u t e}{1 h o u r} = \frac{0.20 \times 60}{h o u r}$
Thus, the hotel charges $0.20 \times 60$ per hour to use the meeting‑room phone.
Therefore, the cost $c$ , in dollars, for $h$ hours of use is $c = (0.20 \times 60) h$ which is equivalent to $c = 0.20 (60 h)$ .

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△ A B C,

A = 60^{\circ}

\frac{b}{c + a} + \frac{c}{a + b} =

∠ C = 60^{0}

\frac{1}{a + c} + \frac{1}{b + c} = \frac{3}{a + b + c}

Δ A B C

∠ C = 60^{\circ}

\frac{1}{a + c} + \frac{1}{(b + c)} = \frac{k}{a + b + c}

k

A B C

∠ A = 60^{o}

(1 + \frac{a}{c} + \frac{b}{c}) (1 + \frac{c}{b} - \frac{a}{b})

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