The count of bacteria in a culture grows by $10 %$ in the first hour, decrease by $8 %$ in the second hour and again increases by $12 %$ in the third hour. If the count of bacteria in the sample is 13125000, what will be the count of bacteria after 3 hours?

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Solution

Present count of bacteria = 13125000
In first hour increase $= 10 %$
decrease in second hour $= 8 %$
increase in third hour $= 12 %$
$∴$ Count of bacteria after 3 hours
$= 13125000 (1 + \frac{10}{100}) (1 - \frac{8}{100}) (1 + \frac{12}{100})$
$= 13125000 \times \frac{11}{10} \times \frac{23}{25} \times \frac{28}{25}$
$= 2100 \times 11 \times 23 \times 28 = 14876400$

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The count of bacteria in a culture grows by 10% in the first hour, decrease by 8% in the second hour and again increases by 12% in the third hour. If the count of bacteria in the sample is 13125000, what will be the count of bacteria after 3 hours?

Present count of bacteria = 13125000 In first hour increase =10% decrease in second hour =8% increase in third hour =12% ∴ Count of bacteria after 3 hours =13125000(1+10100)(1−8100)(1+12100) =13125000×1110×2325×2825 =2100×11×23×28=14876400

The count of bacteria in a culture grows by $10 %$ in the first hour, decrease by $8 %$ in the second hour and again increases by $12 %$ in the third hour. If the count of bacteria in the sample is 13125000, what will be the count of bacteria after 3 hours?