Question

The count of bacteria in a culture was initially $5,25,000$. If it is increasing at the rate of $3\frac{1}{2}\%$ per hour, find the count of bacteria at the end of $2$ hours.

Answer 1

Here, $P=5,25,000,R=3\frac{1}{2}\%$ or $\frac{7}{2}\%$ and $T=2$

Using, $A=P+(1+\frac{R}{100}{)}^T$, we get,

$=5,25,000+(1+\frac{7}{200}{)}^2$

$=5,25,000+(\frac{207}{200}{)}^2$

$=5,25,000\times \frac{207}{200}\times \frac{207}{200}$

$=5,62,393$ approx.

Therefore, after $2$ hours there will be $5,62,393$ bacteria.