The covalency of $N$ in $N H_{4}^{+}$ ion is equal to number of:

covalent bonds

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co ordinate bonds

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covalent bonds and co ordinate bonds

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valence electrons

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Solution

The correct option is C covalent bonds and co ordinate bonds
Covalency of nitrogen = 3{ $σ$ - bond (covalent bond)} +2{1-co-ordinative bonds}
=5

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