The covalent radius of arsenic atom is 1.21 A and effective nuclear charge of 4p electrons is equal to 6.4 What is the electronegativity of arsenic atom

Open in App

Solution

Dear Student,
GIVEN: Z_eff= 6.4 , r_covalent= 1.21
To find the electronegativity allred-Rochow gave a formula which is as follows
$X = (\frac{0.3590 \times Z_{e f f}}{r^{2} C o v a l e n t}) + 0.744$
$X = \frac{0.3590 \times 6.4}{(1.21)} + 0.744$
X=2.3 1
Regards!

Suggest Corrections

Similar questions

Q. Covalent radius of oxygen is 0.74 Å and its electronegativity is 3.5 . find effective nuclear charge experienced by oxygen?
Allred- Rochow electronegativityis given by

χ = \frac{0.359 Z_{e f f}}{r^{2}} + 0.744

where

χ

is electronegativity,

r

= atomic radius,

Z_{e f f}

is effective nuclear charge

Q. Covalent radius of oxygen is 0.74 A

^{o}

and its A.R. electronegativity is 3.5. What is effective nuclear charge experienced by oxygen?

(Round-off to the nearest integer).

Q. The oxidation number of arsenic atom in

H_{3} A s O_{4}

is:

Ionization energy is directly proportional to the atomic radius and the effective nuclear charge.

The bromine atom possesses 35 electrons. It contains 6 electrons in 2p orbital, 6 electrons in 3p orbital and 5 electrons in 4p orbital. Which of these electron experiences the lowest effective nuclear charge?

Join BYJU'S Learning Program

The covalent radius of arsenic atom is 1.21 A and effective nuclear charge of 4p electrons is equal to 6.4 What is the electronegativity of arsenic atom

Dear Student, GIVEN: Zeff= 6.4 , rcovalent= 1.21 To find the electronegativity allred-Rochow gave a formula which is as follows X=( 0.3590×Zeffr2Covalent)+0.744 X=0.3590×6.4(1.21)+0.744 X=2.3 1 Regards!

Dear Student,
GIVEN: Z_eff= 6.4 , r_covalent= 1.21
To find the electronegativity allred-Rochow gave a formula which is as follows
$X = (\frac{0.3590 \times Z_{e f f}}{r^{2} C o v a l e n t}) + 0.744$
$X = \frac{0.3590 \times 6.4}{(1.21)} + 0.744$
X=2.3 1
Regards!