Question

The cranks shaft of a reciprocating engine has a cranck of length 20 cm and a connecting rod of length 100 cm that rotates at 205 rpm. When the crank angle is ${45}^{\circ }$ then what will be the velocity of piston?

• A. 2.48 m/s
• B. 2.96 m/s
• C. 3.64 m/s
• D. 3.46 m/s

Answer 1

The correct option is D 3.46 m/s

As per given information,

$n=\frac{l}{r}=\frac{100}{20}=5$

$V_{approx}=r\omega (sin\theta +\frac{sin2\theta }{60})=0.2\times \frac{2\pi \times 205}{60}(sin{45}^{\circ }+\frac{sin{90}^{\circ }}{2\times 5})$

$=3.46m/s$