The critical angle for a light ray travelling from a denser to rarer medium is defined as the angle of incidence at which the light refracts at 90°(angle of refraction).

If a ray of light travels from water (μ_w) to air (μ_a). Find the critical angle.

Sin^-1 (μ_w/ μ_a)

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sin^-1 (μ_a/μ_w)

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cos^-1 (μ_w/ μ_a)

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Solution

The correct option is B
sin^-1 (μ_a/μ_w)

Apply Snell's law at interface

$μ_{w} s i n i_{c} = μ_{a} s i n 90^{\circ}$

$i_{c} = s i n^{- 1} (\frac{μ_{a}}{μ_{w}})$

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The critical angle for a light ray travelling from a denser to rarer medium is defined as the angle of incidence at which the light refracts at 90°(angle of refraction). If a ray of light travels from water (μw) to air (μa). Find the critical angle.

The correct option is B sin-1 (μa/μw) Apply Snell's law at interface μw sin ic=μa sin 90∘ ic=sin−1 (μaμw)

The critical angle for a light ray travelling from a denser to rarer medium is defined as the angle of incidence at which the light refracts at 90°(angle of refraction).

If a ray of light travels from water (μ_w) to air (μ_a). Find the critical angle.

The correct option is B
sin^-1 (μ_a/μ_w)

Apply Snell's law at interface

$μ_{w} s i n i_{c} = μ_{a} s i n 90^{\circ}$

$i_{c} = s i n^{- 1} (\frac{μ_{a}}{μ_{w}})$