The critical angle for refraction from glass to air is $30^{o}$ and that from water to air is $37^{o}$ . Find the critical angle for refraction from glass to water.

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Solution

From Snell's Law we get $n_{i} s i n θ_{i} = n_{r} s i n θ_{r} => s i n θ_{c} = \frac{n_{r}}{n_{i}} θ_{c} = {s i n}^{- 1} (\frac{30}{37}) = {54.17}^{0}$

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