Question

The critical angle of light going from medium A to medium B is θ, The speed of light in medium A is v. The speed of light in medium B is

• A. $\frac{v}{\sin \theta }$
• B. $\frac{v}{\cos \theta }$
• C. $v\sin \theta$
• D. $v\cos \theta$

Answer 1

The correct option is A $\frac{v}{\sin \theta }$

$\sin {\theta }_C=\sin \theta =\frac{{\mu }_R}{{\mu }_D}=\frac{C/V_B}{C/V_A}=\frac{V_A}{V_B}=\frac{V}{V_B}$
$\therefore V_B=\frac{V}{\sin \theta }$