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Question

The critical angle will be maximum when light travels from


A

glass to air

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B

water to air

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C

glass to water

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D

water to glass

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Solution

The correct option is C

glass to water


The explanation for the incorrect options:

Option A: Glass to air

When the ray goes from glass (denser) to air (rarer) medium, the critical angle is given by sinc=1μga=1μgμa=11.51=11.5

Option B: Water to air

When the ray goes from water (denser) to air (rarer) medium, the critical angle is given by sinc=1μwa=1μwμa=11.331=11.33

Option D: Water to glass

The critical angle is not observed when the ray goes from water (rarer medium) to glass (denser medium).

Explanation for the correct option:

Option C: Glass to water

  1. The critical angle is the angle of incidence for which the angle of refraction is 90° when the rays goes from denser to rarer medium.
  2. The relationship between the critical angle and the refractive index of denser medium with respect to rarer medium is given by sinc=1μ21 where c is the critical angle and μ21 is the refractive index of denser medium with respect to rarer medium.
  3. The refractive index of glass is given by μg=1.5 and for water is μw=1.33=43.
  4. When the ray goes from glass (denser) to water (rarer) medium, the critical angle is given by sinc=1μgw=1μgμw=11.51.33=11.127
  5. The lowest denominator value is 1.127. So the critical angle would be maximum when the ray goes from glass (denser) to water (rarer) medium.

Thus, the critical angle will be maximum when light travels from glass to water.

Hence, option (C) is correct.


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