Question

The critical temperatures of ${\mathrm{CO}}_2$ gas and ${\mathrm{N}}_2$ gas are ${31}^{\mathrm{o}}\mathrm{C}$and $-{147}^{\mathrm{o}}\mathrm{C}$, respectively. Which gas is liquefied easily and why?

Answer 1

The critical temperature of ${\mathrm{CO}}_2$(Carbon dioxide) and ${\mathrm{N}}_2$(Nitrogen) gas are ${31}^{\mathrm{o}}\mathrm{C}$and $-{147}^{\mathrm{o}}\mathrm{C}$ respectively.

As we know that the critical temperature of ${\mathrm{CO}}_2$(Carbon dioxide) is high. This is because the intermolecular forces of attraction among the ${\mathrm{CO}}_2$ molecules are more as compared to ${\mathrm{N}}_2$(Nitrogen). Hence, ${\mathrm{CO}}_2$ can be liquified very easily.