The critical volume and critical pressure for CO gas are 0.09m3 and 0.1 atm respectively.Calculate the value of critical temperature in Kelvin?

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Solution

$Crtical pressure = 0.1 atm Critical volume = 0.09 m^{3} Crtical temperature = \frac{8 a}{27 Rb} a and b are vander waal constant R is gas constant Crtical volume = 3 b 0.09 = 3 b b = 0.03 Critical pressure = \frac{a}{27 b^{2}} 0.1 = \frac{a}{27 {(0.03)}^{2}} a = 0.1 \times 27 {(0.03)}^{2} Now, Critical temperature = \frac{8 a}{27 Rb} = \frac{8 \times 0.1 \times 27 {(0.03)}^{2}}{27 \times 0.03 \times 0.0821} = 0.292 K Regards$ Dear Student

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