Question

The cross of AaBb$\times$AaBb produces offspring with different phenotype, the possible number is

• A. $2$
• B. $4$
• C. $16$
• D. $25$
• E. $50$

Answer 1

The correct option is C $16$

Genotype of parents is AaBb. Since Aa x Aa= 3 Dominant : 1 recessive and Bb x Bb= 3 dominant : 1 recessive; the phenotypic ratio by cross between parents with AaBb genotype= (3 Dominant : 1 recessive) (3 Dominant : 1 recessive)= 9:3:3:1. Total phenotpic combination= 16. Thus, the correct answer is option C.