Question

The cross-sectional area of a wire is $1.0\times {10}^{-7}{m}^2$ and the density of free electrons is $2.0\times {10}^{28}{m}^{-3}$ What will be the drift velocity of the free electrons for a current of $3.2A$ in the wire?

Answer 1

The drift velocity is given as,

$v_d=\frac{I}{nAe}$

$v_d=\frac{3.2}{2\times {10}^{28}\times 1\times {10}^{-7}\times 1.6\times {10}^{-19}}$

$=0.01m/s$

Thus, the drift velocity is $0.01m/s$.