You visited us 1 times! Enjoying our articles? Unlock Full Access!

Lattice Energy

The crystal f...

Question

The crystal field-spliting order for $C r^{3 +}$ cation is octahedral field for ligands $C H_{3} C O O^{-}, N H_{3}, H_{2} O, C N^{-}$ is

C H_{3} C O O^{-} < H_{2} O < N H_{3} < C N^{-}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C H_{3} C O O^{-} < N H_{3} < H_{2} O < C N^{-}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

H_{2} O < C H_{3} C O O^{-} < N H_{3} < C N^{-}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

N H_{3} < C H_{3} C O O^{-} < H_{2} O < C N^{-}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $C H_{3} C O O^{-} < H_{2} O < N H_{3} < C N^{-}$
The crystal field-splitting order for $C r^{3 +}$ cation is octahedral field for ligands $C H_{3} C O O^{-}, N H_{3}, H_{2} O, C N^{-}$ is $C H_{3} C O O^{-} < H_{2} O < N H_{3} < C N^{-}$ .
This is based on the order of the ligands in the spectrochemical series.

Suggest Corrections

Similar questions

C r^{3 +}

I^{-}, H_{2} O, N H_{3}, C N^{-}

O H^{-}

F^{-}

I^{-}

N H_{3}

C H_{3} C O O^{-}

e n

C N^{-}

C l^{-}

H_{2} O

F^{-}, I^{-}, C l^{-}

H_{2} O

{S_{N}}^{2}

H_{2} O

^{-} O C H_{3},^{-} O H

C H_{3} C O O^{-}

C H_{3} C O O H + O H^{-} ⇋ C H_{3} C O O^{-} + H_{2} O + q_{1}

H^{+} + O H^{-} ⇋ H_{2} O + q_{2}

C H_{3} C O O H ⇋ C H_{3} C O O^{-} + H^{+}

C H_{3} C O O H + O H^{-} \to C H_{3} C O O^{-} + H_{2} O + q_{1}

H^{+} + O H^{-} \to H_{2} O + q_{2}

C H_{3} C O O H \to C H_{3} C O O^{-} + H^{+}

Join BYJU'S Learning Program