The correct options are
A lie on the circle
|z|=1 C form an equilateral triangle
We know that cube roots of unity
1,ω,ω2 satisfy
|z|=1Also, |1−ω|2=(32)2+(√32)2=3⇒|1−ω|=√3
∣∣ω−ω2∣∣=∣∣√3i∣∣=√3
and |1−ω|2=∣∣
∣∣1−(−12−i√32)∣∣
∣∣=∣∣∣32+i√32∣∣∣=√3
Therefore 1,ω,ω2 form an equilateral triangle.