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Question

The cubic equation which has three roots 1,32i,3+2i is

A
x3+7x2+17x11=0
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B
x37x2+17x11=0
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C
x37x2+17x+1=0
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D
x3+7x28=0
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Solution

The correct option is B x37x2+17x11=0
Roots are 1,32i,3+2i
Sum of roots, S1=1+32i+3+2i=7
S2=1(32i)+1(3+2i)+(32i)(3+2i)
=6+9+2=17
S3=1(32i)(3+2i)=9+2=11
Therefore equation is
x3+(7)x2+17x+(11)=0x37x2+17x11=0

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