Question

The cubical container ABCDEFGH which is completely filled with an ideal (nonviscous and incompressible) fluid, moves in a gravity-free space with a acceleration of $a=a_0(\hat{i}-\hat{j}+\hat{k})$ where $a_0$ is a positive constant. Then the only point in the container shown in the figure where pressure will be minimum at point:

• A. A
• B. B
• C. H
• D. F

Answer 1

The correct option is C H

The pressure in fluid deceases in the direction of its acceleration.

So,

As we go in positive x, negative y and positive z, the fluid pressure will decrease as $a=a_o(\hat{i}-\hat{j}+\hat{k})$

The maximum pressure will be at that point which has lowest, x-coordinate, highest y-coordinate and lowest z-coordinate.

Here, that point is $B(0,a,0)$

option A is correct.

The minimum pressure will be at that point which has highest x and z coordinates, and lowest y-coordinate

Here, that is point- A$(a,0,a)$

Option C is correct.