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Question

The current density at a point is J=(2×104^j) Am2. Find the rate of charge flow through a cross-sectional area S=(2^i+3^j) cm2.

A
6
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B
7
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C
15
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D
20
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Solution

The correct option is A 6
As we know that rate of charge flow is current.
So.
dI=JdS

I=JS

putting the given value

I=[(2×104)^j][(2^i+3^j)×104]

I=6 A

Hence, option (a) is correct.
Why this question ?
For a finite area,
I=JdS
The direction of the current density is the same as the direction of the current. Thus, it is along the motion of the moving charges.
If a current I is uniformly distributed over an area, then
I=JS

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