The current flowing from the battery if the EMF of the battery is 1 Volts:
1 A
Two parallel combination of resistors:
Rparallel = 1×11+1 = 12 for both of them.
Now, they are in series:
R = 0.5 + 0.5 = 1 Ohms.
Current =EMFEquivalent resistance=11=1A