The current flowing through a wire depends on time as $I = 3 t^{2} + 2 t + 5$ . The charge flowing through the cross-section of the wire in time from $t = 0$ to $t = 2 s$ is

22 C

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20 C

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18 C

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5 C

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Solution

The correct option is A $22 C$
Charge $Q = \int_{0}^{2} (3 t^{2} + 2 t + 5) d t$
$= {[t^{3} + t^{2} + 5 t]}_{0}^{2} = 8 + 4 + 10 = 22 C$

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The current flowing through a wire depends on time as I=3t2+2t+5. The charge flowing through the cross-section of the wire in time from t=0 to t=2s is

The correct option is A 22CCharge Q=∫20(3t2+2t+5)dt =[t3+t2+5t]20=8+4+10=22C

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The correct option is A $22 C$
Charge $Q = \int_{0}^{2} (3 t^{2} + 2 t + 5) d t$
$= {[t^{3} + t^{2} + 5 t]}_{0}^{2} = 8 + 4 + 10 = 22 C$