The current flowing through the zener diode in figure is:

20 m A

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25 m A

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15 m A

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5 m A

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Solution

The correct option is D $5 m A$
Using Kirchoff's current law:
$\frac{10 - 5}{500} = I_{1} + \frac{5}{1000}$
$\frac{5}{500} - \frac{5}{1000} = I_{1}$
$\frac{10 - 5}{1000} = I_{1}$
$5 m A = I_{1}$

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