Question

The current flowing through the Zener diode in the figure is

• A. $20\text{mA}$
• B. $10\text{mA}$
• C. $15\text{mA}$
• D. $5\text{mA}$

Answer 1

The correct option is D $5\text{mA}$

From the circuit,

$I=\frac{10-V_Z}{500}=\frac{10-5}{500}$

$=0.01\text{A}=10\text{mA}$

Now, $I_L=\frac{V_Z}{R_L}=\frac{5}{1\times {10}^3}\text{A}=5\text{mA}$


Using $KCL$,

$I=I_Z+I_L$

$\Rightarrow 10=I_Z+5$

$\Rightarrow I_Z=5\text{mA}$

Hence, $\left(\text{D}\right)$ is the correct answer.