The current flowing when a potential difference of $33 V$ is applied across an appliance having a resistance of $110 Ω$ is $I$ . If the same current $(I)$ is to flow through an appliance having a resistance of $500 Ω$ , how much potential difference should be applied across it?

220 V

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250 V

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150 V

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110 V

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Solution

The correct option is C $150 V$
Given :
First case-
Potential difference applied, $V_{1} = 33 V$
Resistance connected, $R_{1} = 110 Ω$
Second case-
Resistance connected, $R_{2} = 500 Ω$
Current in both cases is $I$

According to Ohm's Law,
$V = I R$
$⟹ \frac{V_{1}}{V_{2}} = \frac{I_{1} R_{1}}{I_{2} R_{2}}$
$V_{2} = V_{1} \frac{R_{2}}{R_{1}} ∵ I_{1} = I_{2} = I$
$V_{2} = 33 \times \frac{500}{110} = 150 V$
The required potential difference between its two ends:
$V_{2} = 150 V$

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The current flowing when a potential difference of 33 V is applied across an appliance having a resistance of 110 Ω is I. If the same current (I) is to flow through an appliance having a resistance of 500 Ω, how much potential difference should be applied across it?

The current flowing when a potential difference of $33 V$ is applied across an appliance having a resistance of $110 Ω$ is $I$ . If the same current $(I)$ is to flow through an appliance having a resistance of $500 Ω$ , how much potential difference should be applied across it?