Question

The current gain $\beta$ of a transistor is 50. The input resistance of the transistor, when used in the common emitter configuration, is 1 $k\Omega$. The peak value of the collector a.c. current for an alternating peak input voltage 0.01 V is :-

Answer 1

Given : $R_b=1000\Omega$ $\beta =50$ $V_{in}=0.01$

Input current (base) $I_b=\frac{V_{in}}{R_b}=\frac{0.01}{1000}=0.01mA$

Collector current $I_c=\beta I_b=50\times 0.01=5mA$