Question

The current gain $\beta$ of a transistor is $50$. The input resistance of the transistor, when used in the common emitter configuration, is $1$ $k\Omega$. The peak value of the collector a.c. current for an alternating peak input voltage $0.01$ V is?

• A. $100$ $\mu A$
• B. $250$ $\mu A$
• C. $500$ $\mu A$
• D. $800$ $\mu A$

Answer 1

Answer: (C)

$500$ $\mu A$

voltage gain is $A_v=\beta \frac{R_c}{R_B}$

$I_c=\frac{A_v{V}_m}{R_b}$

$=\frac{\beta V_m}{R_m}=\frac{50\times 0.01}{{10}^3}$

$5\times {10}^{-4}A=500\mu \alpha$