The current gain of a common base transistor circuit is $0.96$ . On changing the emitter current by $10.0$ mA, the change in the collector current will be.

9.6

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0.4

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19.6

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24

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Solution

The correct option is A $9.6$ mA
Current gain for common bases transistor
$α = {(\frac{Δ I_{C}}{Δ I_{E}})}_{V_{C}}$

Given $α = 0.96, Δ I_{E} = 10.0$ mA

$0.96 = \frac{Δ I_{C}}{10.0}$

$Δ I_{C} = 0.96 \times 10.0 = 9.6$ mA.

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The current gain of a common base transistor circuit is 0.96. On changing the emitter current by 10.0mA, the change in the collector current will be.

The correct option is A 9.6mACurrent gain for common bases transistorα=(ΔICΔIE)VCGiven α=0.96,ΔIE=10.0mA0.96=ΔIC10.0ΔIC=0.96×10.0=9.6mA.

The current gain of a common base transistor circuit is $0.96$ . On changing the emitter current by $10.0$ mA, the change in the collector current will be.

The correct option is A $9.6$ mA
Current gain for common bases transistor
$α = {(\frac{Δ I_{C}}{Δ I_{E}})}_{V_{C}}$

Given $α = 0.96, Δ I_{E} = 10.0$ mA

$0.96 = \frac{Δ I_{C}}{10.0}$

$Δ I_{C} = 0.96 \times 10.0 = 9.6$ mA.