You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Physics

Electric Generator

The current g...

Question

The current generator I_g' shown in figure, sends a constant current i through the circuit. The wire ab has a length l and mass m and can slide on the smooth, horizontal rails connected to I_g. The entire system lies in a vertical magnetic field B. Find the velocity of the wire as a function of time.

Open in App

Solution

Because current i passes through the sliding wire, the magnetic force on the wire (F) is ilB.
Now,
Acceleration of the sliding wire, a = $\frac{i l B}{m}$
Velocity of the sliding wire, v = u + at
∵ u = 0
∴ v = $\frac{i l B t}{m}$

Suggest Corrections

Similar questions

Q. The current generator,

I_{g}

, sends a constant current

1 A

through the circuit. The wire

cd

is fixed and

ab

is made to slide on the smooth thick rails with a constant velocity

20 m/s

towards right in a magnetic field of magnitude

1.5 T

. Each of these wires has resistance

5 Ω

and length of each wire is

0.5 m

. Find the current through the wire

cd

Q. Figure shows a wire

a b

of length

l

and resistance

R

which can slide on a smooth pair of rails in a uniform magnetic field

B

I_{g}

is a current generator which supplies a constant current

i

in the circuit. If the wire

a b

slides at a speed

v

towards the right, find the potential difference

V_{a} - V_{b}

Q. The current generator I_g' shown in figure, sends a constant current i through the circuit. The wire cd is fixed and ab is made to slide on the smooth, thick rails with a constant velocity v towards right. Each of these wires has resistance r. Find the current through the wire cd.

Q. The figure shows a smooth pair of thick metallic rails connected across a battery of emf

ε

having a negligible internal resistance. A wire

a b

of length

l

and resistance

r

can slide smoothly on the rails. The entire system lies in a horizontal plane and is immersed in a uniform vertical magnetic field

B

. At any instant, the wire is given a small velocity

v

towards the right. Find the current in the arrangement at this instant.

Figure (38-E23) shows a smooth pair of thick metallic rails connected across a battery of emf $ε$ having a negligible internal resistance. A wire ab of length l and resistance r can slide smoothly on the rails. The entire system lies in .a horizontal plane and is immersed in a uniform vertical magnetic field B. At an instant t, the wire is given a small velocity u towards right. (a) Find the current in it at this instant. What is the direction of the current ? (b) What is the force acting on the wire at this instant ? (c) Show that after some time the wire ab will slide with a constant velocity. Find this velocity.

Join BYJU'S Learning Program

The current generator Ig' shown in figure, sends a constant current i through the circuit. The wire ab has a length l and mass m and can slide on the smooth, horizontal rails connected to Ig. The entire system lies in a vertical magnetic field B. Find the velocity of the wire as a function of time.

Because current i passes through the sliding wire, the magnetic force on the wire (F) is ilB. Now, Acceleration of the sliding wire, a = ilBm Velocity of the sliding wire, v = u + at ∵ u = 0 ∴ v = ilBtm

Because current i passes through the sliding wire, the magnetic force on the wire (F) is ilB.
Now,
Acceleration of the sliding wire, a = $\frac{i l B}{m}$
Velocity of the sliding wire, v = u + at
∵ u = 0
∴ v = $\frac{i l B t}{m}$