Question

The current $I$ drawn from the $5V$ source in the given circuit will be :

• A. 0.33 A
• B. 0.5 A
• C. 0.67 A
• D. 0.17 A

Answer 1

Answer: (B)

0.5 A

By wheatstone condition the cirucit reducer to.

$Req=\frac{30\times 15}{45}=10\Omega$

$\Rightarrow I=\frac{5}{Req}=\frac{5}{10}=0.5A..$