Apply KVL Loop ABDE, +2 30i_1 = 0 i_1 = 1/15 A → (1) Loop ABCDE + 2 (i i_1) 30 (i i_1) 30 = 0 i i_1 = 1/30 From (1) i = 1/30 + 1/15 = 1/10 A ...

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Kirchoff's Voltage Law

[IIT-JEE 1983...

Question

The current i in the circuit is

[IIT-JEE 1983]

1/45 A

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1/15 A

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1/10 A

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1/5 A

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Solution

The correct option is C
1/10 A

Apply KVL
Loop ABDE,
$+ 2 - 30 i_{1} = 0$
$i_{1} = \frac{1}{15} A \to (1)$

Loop ABCDE
$+ 2 - (i - i_{1}) 30 - (i - i_{1}) 30 = 0$
$i - i_{1} = \frac{1}{30}$

From (1)
$i = \frac{1}{30} + \frac{1}{15}$
$= \frac{1}{10} A$

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