Question

The current I in the circuit shown in figure is

• A. $\frac{1}{45}$ A
• B. $\frac{1}{15}$ A
• C. $\frac{1}{10}$ A
• D. $\frac{1}{5}$ A

Answer 1

The correct option is C $\frac{1}{10}$ A

The equivalent resistance is given by
$\frac{1}{R}=\frac{1}{60}+\frac{1}{30}=\frac{3}{60}$
R = 20 ohm. Therefore $I=\frac{2}{20}=\frac{1}{10}A$