Question

The current I in the circuit shown in figure is

• A.
• B.
• C.
• D.

Answer 1

The correct option is C

The equivalent resistance is given by
$\frac{1}{R}=\frac{1}{60}+\frac{1}{30}=\frac{3}{60}R=20ohm.$
Therefore $I=\frac{2}{20}=\frac{1}{10}A$