Question

The current $I$ in the given circuit is-

• A. $\frac{1}{45}\text{A}$
• B. $\frac{1}{15}\text{A}$
• C. $\frac{1}{10}\text{A}$
• D. $\frac{1}{5}\text{A}$

Answer 1

The correct option is C $\frac{1}{10}\text{A}$


In the given circuit, $\text{BC}$ and $\text{CA}$ are in series,

$\therefore R_{BCA}=30+30=60\Omega$

Also, $\text{BCA}$ and $\text{BA}$ are in parallel,

$\therefore \frac{1}{R_{eq}}=\frac{1}{60}+\frac{1}{30}=\frac{3}{60}=\frac{1}{20}$
$\Rightarrow R_{eq}=20\Omega$
$\therefore I=\frac{V}{R_{eq}}=\frac{\text{2}}{20}=0.1\text{A}$

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, $\left(C\right)$ is the correct answer.