Question

The current I through 10 $\Omega$ resistor in the circuit shown in figure.

• A. 50 mA
• B. 20 mA
• C. 40 mA
• D. 80 mA
• E. 35 mA

Answer 1

The correct option is D 80 mA

In the given circuit, junction diode $D_1$ if forward biased, will conduct current and junction diode $D_2$ is reverse biased, will not conduct current. Therefore, current
I = $\frac{2}{10+15}$ = 0.08 A = 80 mA.