Question

The current I through $10\Omega$ resistor in the circuit with ideal diodes shown in the figure is

• A. 50 mA
• B. 20 mA
• C. 40 mA
• D. 80 mA

Answer 1

The correct option is D 80 mA

$D_1$ is forward biased and $D_2$ is reverse biased. Thus

$i=\frac{2}{25}$
$=0.08=80mA$