The current in a discharging LR circuit without the battery drops from 2.0A to 1.0A in 0.10s. (a) Find the time constant of the circuit. (b) If the inductance of the circuit is 4.0H, what is its resistance?
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Solution
(a) for discharging circuit i=i0e−t/τ⇒1=2e−0.1/τ⇒(1/2)=e−0.1/τ⇒ln(1/2)=ln(e−0.1/τ)⇒τ=0.1/0.693=0.144=0.14 (b) L=4H,i=L/R ⇒0.14=4R ⇒R=4/0.14=28.57=28Ω